SSC JE Civil Engineering 2014 Set 1 Solved Paper

Question : 113 of 200

Marks: +1, -0

The plan of a building is in the form of a rectangle with centre line dimensions of the outer walls as 10.3 m × 15.3 m. The thickness of the walls in superstructure is 0.3 m. Then its carpet area is

150 $m^2$
157.59 $m^2$
165.36 $m^2$
170 $m^2$

Validate

Solution:

Carpet area: carpet area is the useful area which excludes corridors, staircase, passages, verandas, lifts etc.
Carpet area = [(15.3 – 0.3)  (10.3 – 0.3)]

= 150\m^2

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