SSC JE Civil Engineering 2013 Solved Paper

In thin cylindrical shell
Longitudinal stress $=\frac{\mathit{p}\mathit{d}}{4\mathit{t}}$
Hoop stress σH $=\frac{\mathit{p}\mathit{d}}{2\mathit{t}}$
p ⇒ fluid pressure
d ⇒ diameter of pipe
i ⇒ thickness of cylinder shell
The ratio of longitudinal to hoop stress $=\frac{\frac{\mathit{p}\mathit{d}}{4\mathit{t}}}{\frac{\mathit{p}\mathit{d}}{2\mathit{t}}}$ $=\frac{1}{4}\times \frac{2}{1}=0.5$