SSC JE Civil Engineering 2012 Solved Paper

Question : 132 of 200

Marks: +1, -0

The beam shown below is indeterminate of degree -

Solution:

D_S = Di + De

D_i = 5 -3 = 2

D_e

= 3m – (3j – 3) = 3 × 2 – (3 × 3 – 3) = 0

D_s

= 0 + 2 = 2

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