Find the value of [(27 \times 3) \times \{3 \div 3 \times \frac{(19−15)}{4}\} ]

SSC GD Constable 6 Feb 2025 Shift 2 Paper

Section: Elementary Mathematics

Question : 56 of 80

Marks: +1, -0

Find the value of

[(27 × 3) × \{3 ÷ 3 × \;{(19−15)}/{4}\} ]

Solution:

\;{ [(27 × 3) × \{3 ÷ 3 × \;{(19-15)}/{4}\} ] }

\;⇒ [(27 × 3) × \{3 ÷ 3 × \;{4}/{4}\} ]

\;⇒ [(27 × 3) × \{1 × \;{4}/{4}\} ]

\;⇒[(27 × 3) ×\{1 × 1\}]

\;⇒[(27 × 3) × 1]

\;⇒[81 × 1]

\;⇒ 81

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