Find the value of [(91 \div 7) \times \{\frac{64}{4} + \frac{17}{6} \times (8−2)\} ]

SSC GD Constable 5 Feb 2025 Shift 2 Paper

Section: Elementary Mathematics

Question : 49 of 80

Marks: +1, -0

Find the value of

[(91 ÷ 7) × \{\;{64}/{4} + \;{17}/{6} × (8−2)\} ]

Solution:

Order of operations (BODMAS): Solve inside brackets first, then division/multiplication, and finally addition/subtraction.
Calculation:

\;⇒[(91 ÷ 7) ×\{(64 ÷ 4)+(17 ÷ 6) ×(8-2)\}]

\;⇒(13) ×\{(16)+(17 ÷ 6) ×(6)\}

\;⇒(13) ×\{16+(17 × 6 ÷ 6)\}

\;⇒(13) ×\{16+17\}

\;⇒ 13 × 33

\;⇒ 429

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