SSC GD Constable 5 Feb 2025 Shift 2 Paper

Relative Speed = Speed of Train 2 - Speed of Train 1 (as both trains are moving in the same direction)
Time $=$ Distance $∕$ Speed
Calculation:
Distance to be covered $=$ Length of Train $1+$ Length of Train 2 $=170+480=650\mathit{m}$
Relative Speed $=$ Speed of Train $2-$ Speed of Train 1 $=80-70=10\mathit{k}\mathit{m}∕\mathit{h}$
Convert relative speed to $\mathit{m}∕\mathit{s}$ :
Relative Speed $=10\times \left(1000∕3600\right)=10\times 5∕18=50∕18\mathit{m}∕\mathit{s}$
Time $=$ Distance $∕$ Speed
⇒ Time $=650∕\left(50∕18\right)$
⇒ Time $=650\times \left(18∕50\right)$
⇒ Time $=\left(650\times 18\right)∕50$
⇒ Time $=11700∕50$
⇒ Time $=234$ seconds
Convert time to minutes:
⇒ Time $=234∕60=3.9$ minutes