SSC GD Constable 5 Feb 2025 Shift 1 Paper

Section: Elementary Mathematics

Question : 49 of 80

Marks: +1, -0

The smallest natural number which is divisible by 26, 8, 11 and 13 is:

Solution:

To find the smallest number divisible by these numbers, we need to calculate the LCM (Least Common Multiple).
Calculation:
Prime factorization:

\;26=2 × 13

\;8=2^3

\;11=11

\;13=13

\;LCM=\;\text " Highest power of each prime factor present in the numbers: "\;

\;LCM=2^3 × 11 × 13

\;⇒ LCM=8 × 11 × 13

\;⇒ LCM=1144

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