SSC GD Constable 4 Feb 2025 Shift 3 Paper

Let the original price of fuel be $\mathit{₹}100$.
After the first month (40\% decrease):
Price after $40\%$ decrease $=100\times \left(1-40∕100\right)=100\times 0.60=\mathit{₹}60$
After the second month (10\% decrease):
Price after $10\%$ decrease $=60\times \left(1-10∕100\right)=60\times 0.90=\mathit{₹}54$
After the third month (50\% decrease):
Price after 50\% decrease $=54\times \left(1-50∕100\right)=54\times 0.50=\mathit{₹}27$
After the fourth month (50\% increase):
Price after 50\% increase $=27\times \left(1+50∕100\right)=27\times 1.50=\mathit{₹}40.5$
Percentage change $=\left[\right($ Final Price - Original Price $)∕$ Original Price $]\times 100$
Percentage change $=\left[\left(40.5-100\right)∕100\right]\times 100$
Percentage change $=\left(-59.5∕100\right)\times 100=-59.5\%$