SSC GD Constable 4 Feb 2025 Shift 3 Paper

Let the amount Mahesh gave to Vijay be ₹x and to Ajay be ₹(1617 - x).
According to the given condition, Vijay and Ajay received the same amount after 13 and 14 years, so we can write the equation for their amounts:
$\mathit{x}{\left(1+10∕100\right)}^{13}=\left(1617-\mathit{x}\right){\left(1+10∕100\right)}^{14}$
$\Rightarrow \mathit{x}{\left(1.1\right)}^{13}=\left(1617-\mathit{x}\right){\left(1.1\right)}^{14}$
Divide both sides by ${\left(1.1\right)}^{13}$ :
$\Rightarrow \mathit{x}=\left(1617-\mathit{x}\right)\left(1.1\right)$
$\Rightarrow \mathit{x}=1617\times 1.1-\mathit{x}\times 1.1$
$\Rightarrow \mathit{x}+\mathit{x}\times 1.1=1617\times 1.1$
$\Rightarrow \mathit{x}\left(1+1.1\right)=1617\times 1.1$
$\Rightarrow \mathit{x}\times 2.1=1617\times 1.1$
$\Rightarrow \mathit{x}=\left(1617\times 1.1\right)∕2.1$
$\Rightarrow \mathit{x}=1778.7∕2.1$
$\Rightarrow \mathit{x}=\mathit{₹}846.43\approx \mathit{₹}847$