SSC GD Constable 4 Feb 2025 Shift 3 Paper

Volume of a sphere $=\frac{4}{3}\mathit{\pi }{\mathit{r}}^3$
Calculation:
Volume of the original sphere $=\frac{4}{3}\mathit{\pi }{\mathit{r}}^3$
Volume of the new sphere $=\frac{4}{3}\mathit{\pi }{\left(3\mathit{r}\right)}^3$
⇒ Volume of the new sphere $=\frac{4}{3}\mathit{\pi }\left(27{\mathit{r}}^3\right)$
⇒ Volume of the new sphere $=27\times \frac{4}{3}\mathit{\pi }{\mathit{r}}^3$
⇒ Volume of the new sphere $=27\times$ Volume of the original sphere
Ratio of the volume of the original sphere to the new sphere $=1:27$