Find the value of [(84 \div 6) \times \{\frac{91}{7} + \frac{16}{2} \times (8−6)\} ]

SSC GD Constable 4 Feb 2025 Shift 2 Paper

Section: Elementary Mathematics

Question : 58 of 80

Marks: +1, -0

Find the value of

[(84 ÷ 6) × \{\;{91}/{7} + \;{16}/{2} × (8−6)\} ]

Solution:

Perform operations inside brackets first, then solve from innermost to outermost brackets.
Calculations:

\;⇒[(84 ÷ 6) ×\{(91 ÷ 7)+(16 ÷ 2) ×(8-6)\}]

\;⇒[(84 ÷ 6) ×\{13+8 × 2\}]

\;⇒[14 ×\{13+16\}]

\;⇒[14 × 29]

\;⇒ 406

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