SSC GD Constable 4 Feb 2025 Shift 2 Paper

To find the ratio $\mathit{A}:\mathit{B}:\mathit{C}$, we can equate each term to a common variable and solve for $\mathit{A},\mathit{B}$, and C .
Calculations:
Let $7\mathit{A}=6\mathit{B}=12\mathit{C}=\mathit{k}$
Then,
$\mathit{A}=\mathit{k}∕7$
$\mathit{B}=\mathit{k}∕6$
$\mathit{C}=\mathit{k}∕12$
$\mathit{A}:\mathit{B}:\mathit{C}=\mathit{k}∕7:\mathit{k}∕6:\mathit{k}∕12$
To remove the fractions, multiply each term by the LCM of the denominators $\left(7,6,12\right)$, which is 84.
$\mathit{A}:\mathit{B}:\mathit{C}=\left(\mathit{k}∕7\right)\times 84:\left(\mathit{k}∕6\right)\times 84:\left(\mathit{k}∕12\right)\times 84$
$\mathit{A}:\mathit{B}:\mathit{C}=12\mathit{k}:14\mathit{k}:7\mathit{k}$
Since ' k ' is common, we can eliminate it.
$\mathit{A}:\mathit{B}:\mathit{C}=12:14:7$