SSC GD Constable 4 Feb 2025 Shift 2 Paper

Section: Elementary Mathematics

Question : 52 of 80

Marks: +1, -0

Rajeshwar can do a piece of work in 12 days, Vikram in 6 days and Tiger in 15 days. They all start the work together, but Rajeshwar leaves after 2 days and Vikram leaves 3 days before the work is completed. In how many days is the work completed?

$5\;{4}/{7}$
$5\;{5}/{7}$
$5\;{3}/{7}$
$5\;{6}/{7}$

Validate

Solution:

Total work = LCM of individual work times
Work done

=

Efficiency × Time
Calculations:
LCM of 12, 6, and

15=60

(Total work)
Rajeshwar's efficiency

=60 \/ 12=5

units/day
Vikram's efficiency

=60 \/ 6=10

units/day
Tiger's efficiency

=60 \/ 15=4

units/day
Rajeshwar worked for 2 days, so work done by him

=5 × 2=10

units
Let the total number of days the work was completed be ' x ' days.
Vikram worked for (

x-3

) days.
Tiger worked for x days.
Total work done

=

Rajeshwar's work + Vikram's work + Tiger's work

\;60=10+10(x-3)+4 x

\;⇒ 60=10+10 x-30+4 x

\;⇒ 60=14 x-20

\;⇒ 80=14 x

\;⇒ x=80 \/ 14=40 \/ 7=5 \;{5}/{7} \;\text " days. "\;

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