SSC CPO SI and ASI Model Paper 9

Question : 113 of 200

Marks: +1, -0

If a : b = 3 : 4, find out

(6a^2 – 5b^2) : (a^2 – 2b^2).

Solution:

(1)

a = {3b}/4

(6a^2 – 5b^2) : (a^2 – 2b^2)

=6×{9b^2}/16-{5b^2}:{9b^ 2}/16-2b^2

={13 b^2}/8:{ 23 b^2}/16= 26 : 23

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