SSC CPO SI and ASI Model Paper 7

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Question : 143 of 200

Marks: +1, -0

Find the value of θ, if

{sin}^2/{tan^2-sin^2}= 3 tan sin and 0° < θ≤ 90°

.

90°
45°
60°
30°

Solution:

(4)

{sin^2}/{tan^2-sin^2}=3

⇒{sin^2}/{sin^2}[1/cos^2-1]=3

⇒cos^2/1-cos^2=3

⇒cot^2θ=√3

⇒cotθ=√3(since0°<θ<90°)

⇒cotθ=cot30°

⇒

θ=30°

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