SSC CPO SI and ASI Model Paper 3

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Question : 145 of 200

Marks: +1, -0

If secθ + tanθ

= 1 + √3

, then cosθ is equal to

3
$1/√ 3$
$4/ 1 + 3 √3$
Not defined

Solution:

(3) secθ + tanθ = 1 + √3…..(1)
secθ – tanθ=

1 /{1+ √3}={1 -√3}/(1+√3)(1-√3)={√3-1}/2…..(2)

On solving (1) and (2), we get secθ

= {1 +3 √3}/4

∴ cosθ=

4/{1 + 3 √3}

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