If a^2+ b^2 + c^2 +3=2(a-b-c), then find out the value of 3a + 2b + c.

SSC CPO SI and ASI Model Paper 3

Question : 115 of 200

Marks: +1, -0

a^2+ b^2 + c^2 +3=2

(a-b-c), then find out the value of 3a + 2b + c.

Solution:

(1)

a^2 + b^2 + c^2 +3=2 (a-b-c)

a^2 b^2 c^2

2a 2b 2c 3 0

a^2 –2a +1+ b^2 + 2b + 1+ c^2+2c+1=0

(a–1)^2+ (b+1)^2+ (c+1)^2=0

a = 1, b = -1, c = –1
∴ 3a + 2b + c
= 3 – 2 – 1 = 0

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