If tanθ= 3 /4 , then find the value of { 4sin\theta+2cos\theta}/ {4sin\theta–2cos\theta }.

SSC CPO SI and ASI Model Paper 10

Question : 108 of 200

Marks: +1, -0

If tanθ= 3 /4 , then find the value of

{ 4sinθ+2cosθ}/ {4sinθ–2cosθ }

Solution:

(1)

{ 4sinθ+2cosθ}/ {4sinθ–2cosθ }

.
On dividing both numerator anddenominator by cosθ, we get

{ 4sinθ+2}/ {4sinθ–2 }={3+2}/{3-2}=5

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