SSC CPO SI and ASI Model Paper 1

Question : 141 of 200

Marks: +1, -0

Angles of depression from the top of a pole to two points are 45° and 30°, respectively. If distance between the two points is 20 m, then what is the height of the pole?

$20(√ 3 -1)m$
$20/{ √3 +1 }m$
$10(√3 +1)m$
30 m

Validate

Solution:

(3) Let height of the pole be h m.

tan45° h/BC⇒ hmetre , nowtan

30°=h/{BC+ 20} =h /{h+20}

⇒h√ 3 h +20

⇒h=20/{√3- 1}

10(√ 3 +1 )m

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