SSC CPO SI and ASI Model Paper 1

Question : 106 of 200

Marks: +1, -0

Four discs, each having radius 24 cm, are placed in such a manner that each disc touches the other two discs. What would be the area enclosed by the four discs?

$493.72 cm^2$
$200.56 cm^2$
$483.25 cm^2$
$245.52 cm^2$

Validate

Solution:

Required area = Area of shadedregion = area of square ABCD – 4 ×(area of a sector)

=48× 48- 4{n×24 ×24}/4

= 2304 -1810.28= 493.72 cm^2

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