SSC CPO SI and ASI 2016 Paper

Question : 111 of 200

Marks: +1, -0

A number, when increased by 15% and then decreased by 25%, becomes 22 less than the original number. The original number is

Solution:

(2) Let the original number be a,
then
Net change

=15-25+ {15 ×-25}/{100}=- {55}/{4} \%

( ∵

Net change

=a+b+{a b} / 100)

So,

{55}/{4} \%

a=22 ⇒ a= {22 × 100 × 4}/{55}=160

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