SSC CPO SI and ASI 2015 Paper

Question : 28 of 199

Marks: +1, -0

A man starts a journey from home. He goes 5 km to the north, then proceeds 10 kms to the right. From there, he again turns right and goes 10 km. How far is he from home? All distances are measured aerially.

$√200$
$√ 150$
$√ 225$
$√ 125$

Validate

Solution:

(4)

In triangle AOB, AO = 10 km, OB = 10 – 5 = 5 km. Now, He is AB =

√{5^{2}+10^{2}}=\√{125}

km far from his house.

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