SSC CPO SI and ASI 2015 Paper

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Question : 145 of 199

Marks: +1, -0

If sec x + cos x = 2, then the value of sec

^{16}

x + cos

^{16}

x will be

$√{3}$
2
1
0

Solution:

(2)

(\sec x+\cos x)^{2}=4

\⇒ \sec ^{2} x+\cos ^{2} x=2

Now,

\ (\sec ^{2} x+\cos ^{2} x\ )^{2}=4

⇒ \sec ^{4} x+\cos ^{2} x=2

Similarly,

\sec ^{16} x+\cos ^{16} x=2

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