SSC CPO SI and ASI 2014 Paper

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Question : 143 of 200

Marks: +1, -0

If cos θ =

3 /5

, then the value of sin θ. sec θ. tan θ is

$9/ 16$
$16 /9$
$3 /4$
$4 /3$

Solution:

(2) Since,cos θ =

3 /5

so sec θ =

5/3

and

\tan \θ=√{\sec ^{2} \θ-1}

=√{ ( {5}/{3} )^{2}-1}= {4}/{3}

Therefore,

\sin \θ . \sec \θ . \tan \θ= {\sin \θ}/{\cos \θ} × \tan \θ

=\tan ^{2} \θ= ( {4}/{3} )^{2}= {16}/{9}

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