Solve for θ: \cos ^{2}\theta − \sin ^{2}\theta = \frac{1}{2}, 0 < θ < 90°.

SSC CPO 25 Nov 2020 Shift 2 Paper

Question : 127 of 200

Marks: +1, -0

Solve for θ:

\cos ^{2}θ − sin \;^{2}θ = \;{1}/{2}

, 0 < θ < 90°.

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