SSC CHSL Model Paper 7

Question : 33 of 100

Marks: +1, -0

The angle of elevation of a cloud from a point 200 m above a lake is 30° and the angle of depression of its reflection in the lake is 60°. The height of the cloud is

200m
300m
400m
600m

Validate

Solution:

\tan30°=\h/\PM⇒\PM=√3\h

\tan60°={\h+400}/\PM⇒\PM={\h+400}/√3

√3\h={\h+400}/√3=3\h- \h = 400

⇒ 2h = 400
⇒ So, height of the cloud = 200 + 200 = 400m

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