SSC CHSL Model Paper 6

Question : 57 of 100

Marks: +1, -0

A large cube is formed from the material obtained by melting three smaller cubes of 3, 4 and 5 cm sides. What is the ratio of the total surface areas of the smaller cubes and the large cube?

2 : 1
3 : 2
25 : 18
27 : 20

Validate

Solution:

Volume of the large cube = (33 + 43 + 53)
= 216 cm

^{3}

.
Let the edge of the large cube be a.
So,

a^3 = 216\;\;\;\;\; a = 6

cm.
Required Ratio:

({6×(3^2+4^2+5^2)}/{6×6^2})

= 25 : 18

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