SSC CHSL Model Paper 5

Question : 38 of 100

Marks: +1, -0

A triangle and a parallelogram are constructed on the same base such that their areas are equal. If the altitude of the parallelogram is 100 m, then the altitude of the triangle is :

100 m
200 m
$100√2$ m
$10√2$ m

Validate

Solution:

Let the common base be x m.
Now, area of the triangle = area of the parallelogram

1/2×π× \Altitude \of \the \triangle

= x × 100

Altitude of the triangle = 200 m

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