SSC CHSL Model Paper 4

Question : 61 of 100

Marks: +1, -0

The least number which when divided by 5, 6 , 7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder, is:

1677
1683
2523
3363

Validate

Solution:

LCM of 5, 6, 7, 8 = 840
Required number is of the form 840k + 3 such that it will leave a remainder of 3 when divided by 5, 6, 7 and 8.
Least value of k for which (840k+ 3) is divisible by 9 is k = 2
Required number

= (840× 2 + 3) = 1683

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