SSC CHSL Model Paper 19

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Question : 63 of 99

Marks: +1, -0

If

\tanθ_1 = 1, \sinθ_2= 1/√2

, then the value of

\sin (θ_1 + θ_2)

equals to

-1
0
1
$1/2$

Solution:

\tanθ_1 = 1=\tan45°

⇒θ_1=45°

\Again, \sinθ_2= 1/√2=\sin45°

⇒

θ_2=45°

∴

\sin (θ_1 + θ_2) = \sin 90° = 1

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