SSC CHSL Model Paper 19

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Question : 55 of 99

Marks: +1, -0

ΔABC - ΔQPR and AB = 8 cm, BC =12 cm and AC = 6 cm, If ar (ΔABC): ar (ΔPQR) = 16: 25, then RQ is equql to:

12.5 cm
10 cm
15 cm
7.5 cm

Solution:

ΔABC ∼ ΔQPR

{ \ar(\Δ\ABC)}/{ \ar(\Δ\PQR)}=16/25

⇒

\CA^2/\RQ^2=16/25

⇒

6^2/\RQ^2=16/25

⇒

\RQ=√{{36×25}/16}

={6×5}/4=7.5\cm

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