SSC CHSL Model Paper 18

Question : 51 of 100

Marks: +1, -0

Quantitative Aptitude

The circumference of a circle is equal to the sum of the perimeters of an equilateral triangle of side 12 cm and that of a square of diagonal

2√2

cm. Find the area of the circle in cm

^{2}

Solution:

Circumference of circle

12×3+(2√2)^2=44

⇒

2r×22/7=44

⇒

r=7

Area of circle =

πr^2=22/7×7×7=154

sq cm

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