SSC CHSL Model Paper 17

Question : 64 of 100

Marks: +1, -0

If cosec θ

= 13/12

, then sin θ + cos θ - tan θ is equal to:

Solution:

\cosec\θ=13/12

\BC=√{13^2+12^2} =√{169-144}

=√25=5

\sinθ+\cosθ-\tanθ

=12/13+5/13-12/5

={60+25-156}/65

={85-156}/65=-71/65

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