SSC CHSL Model Paper 16

Question : 70 of 100

Marks: +1, -0

Evaluate tan 5° tan 25° tan 30° tan 65° tan 85°

Solution:

tan 5° tan 25° tan 30° tan 65° tan 85°
= cot 85 cot 65 tan 30 tan 65 tan 85
= tan 30 (since cot 85 × tan 85 = 1 and cot 65 × tan 65 = 1)

=1/√3

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