SSC CHSL Model Paper 14

Question : 9 of 100

Marks: +1, -0

Shyam walked 6 m facing towards East, then took a right turn and walked a distance of 9 m. He then took a left turn and walked a distance of 6 m. How far is he from the starting point?

15 m
21 m
18 m
Cannot be determined

Validate

Solution:

The direction in which Shyam travels is represented as below:

In triangle ACB and triangle CDE,
Angle B = angle D = 90°
Angle ACB = angle DCE (Vertically opposite angles)
AB = DE (Given)
Hence, triangle ACB is congruent to triangle ECD.
Thus, CD = BC =

\BD/2

= 4.5
Using Pythagoras theorem , we find that
CE = 7.5
Similarly, AC = 7.5
AE = CA + CE
AE = 15 m

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