SSC CHSL Model Paper 13

Question : 63 of 100

Marks: +1, -0

In a ΔABC, the sides are AB =16 cm, AC = 63 cm, BC = 65 cm. From A, a straight line AM is drawn up to the midpoint M of side BC. Then the length of AM is equal to:

32.5 cm
24.5 cm
23.5 cm
31.5 cm

Validate

Solution:

16^2 + 63^2 = 65^2

\AB^2 + \AC^2 = \BC^2

∴ ΔABC is a right angled triangle.
So,

\AM=\BC/2=65/2=32.5\cm

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