SSC CHSL Model Paper 13

Question : 55 of 100

Marks: +1, -0

ΔABC ~ ΔEDF and AB = 5 cm, BC = 8 cm and AC = 10 cm. If ar (ΔABC) : ar (ΔDEF) = 9:4, then DF is equal to:

Solution:

ΔABC ~ ΔEDF

{\ar(\Δ\ABC)}/{\ar\Δ\EDF}=9/4

{\ar(\Δ\ABC)}/{\ar\Δ\EDF}=\BC^2/\DF^2

⇒\DF^2={64×4}/9

⇒\DF=√{{64×4}/9}=16/3\cm

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