SSC CHSL Model Paper 13

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Question : 51 of 100

Marks: +1, -0

If

(3x- 1)^3 + (4x-3)^3 + (2x +1)^3

= 3 (3x- 1) (4x-3)(2x + 1)

and

x≠1/3

, then

x=

?

$1/2$
2
$1/4$
1

Solution:

(3x- 1)^3 + (4x- 3)^3 + (2x+ 1)^3

= 3(3x- 1) (4x-3) (2x+ 1)

∴ 3x- 1 = 4x- 3 = 2x + 1

⇒ 3x - 1 = 4x - 3

⇒ 4x- 3x = 3 - 1

⇒ x= 2

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