SSC CHSL 9 Jan 2017 Shift 3 Paper

Question : 63 of 100

Marks: +1, -0

A bag has Rs 30.8 in the form of 1 rupee, 50 paise and 10 paise coins in the ratio of 6:3:2. What is the number of 50 paise coins?

Solution:

Let the number of 1 rupee, 50 paise and 10 paise coins be

6x,3x,2x

respectively
Total amount in the bag = Rs 30.8
⇒

(1 × 6x) + ( 50/100 ×3x)

+ ( 10/100 ×2x) = 30.8

⇒

6x + {3x}/2 +x/5 =30.8

⇒

{60x+15x+2x}/10=30.8

⇒

77x = 30.8 × 10 = 308

⇒

x = 308/77 =4

∴ Number of 50 paise coins =

3×4=12

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