SSC CHSL 8 Jan 2017 Shift 3 Paper

Sum for compound interest = Rs. 1200
Rate of interest = 10% and time period = 2 years
Compound interest =$\mathit{P}\left[{\left(1+\frac{\mathit{R}}{100}\right)}^{\mathit{T}}-1\right]$
$=1200\left[{\left(1+\frac{10}{100}\right)}^2-1\right]$
$=1200\left[{\left(\frac{11}{10}\right)}^2-1\right]$ $=1\mathrm{2}00\left(\frac{121-100}{100}\right)$
$=12\times 21=$ Rs.252
⇒ Simple interest = $\frac{252}{2}=\mathit{R}\mathit{s}.126$
Let sum under simple interest = Rs.x
Rate of interest = 8% and time period = 3 years
Simple interest = $\frac{\mathit{P}\times \mathit{R}\times \mathit{T}}{100}$
$=\frac{\mathit{x}\times 8\times 3}{100}=126$
⇒ $\mathit{x}=\frac{126\times 25}{6}=21\times 25=$ Rs.525