SSC CHSL 8 Jan 2017 Shift 1 Paper

Slope of line 2x + 3y = 6 is $\left(-\frac{2}{3}\right)$
Product of slopes of two perpendicular lines = -1
Let slope of line passing through origin = m
⇒ $\mathit{m}\times -\frac{2}{3}=-1$
⇒ $\mathit{m}=\frac{3}{2}$
Equation of line passing through origin and having slope m is (Since y intercept is zero)
⇒ $\mathit{y}=\frac{3}{2}\mathit{x}$
⇒ $3\mathit{x}=2\mathit{y}$
Solving the above equations, we get the intersection point M = $\left(\frac{6}{11},\frac{9}{11}\right)$