SSC CHSL 8 Jan 2017 Shift 1 Paper

Let 11$\mathit{x}$ candidates applied for the process.
Candidates selected = 9$\mathit{x}$ and candidates not selected = 2$\mathit{x}$
If candidates applied = $11\mathit{x}-80$
Candidates selected = $9\mathit{x}-20$
⇒ Candidates not selected = $\left(11\mathit{x}-80\right)-\left(9\mathit{x}-20\right)=2\mathit{x}-60$
According to ques,
⇒ $\frac{9\mathit{x}-20}{2\mathit{x}-60}=\frac{5}{1}$
⇒ $9\mathit{x}-20=10\mathit{x}-300$
⇒ $\mathit{x}=300-20=280$
∴ Number of candidates who applied for the process = $11\times 280=3080$