SSC CHSL 8 Jan 2017 Shift 1 Paper

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Question : 51 of 100

Marks: +1, -0

What is the value of

(4a^2-9b^2)\/(2a+3b)

is

2a - 3b
2a + 3b
2a
3b

Solution:

Expression :

(4a^2-9b^2)\/(2a+3b)

Using

(x^2-y^2)=(x-y)(x+y)

={(2a^2)-(3b^2)}/{2a+3b}

={(2a-3b)×(2a+3b)}/{2a+3b}=2a-3b

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