SSC CHSL 7 Mar 2018 Shift 3 Paper

Section: English Language

Question : 16 of 100

Marks: +1, -0

Two trains are moving in the same direction at the speed of 42 km/hr and 84 km/hr, their lengths are 320 metres and 380 metres respectively. What is the time taken (in seconds) by faster train to cross the slower train?

Validate

Solution:

Let time taken =

t

seconds
The trains are moving in same direction, thus relative speed =

84-42=42

km/hr =

(42×5/18)=35/3

m/s
Total distance = sum of lengths of train =

320 +380 =700

m
Using, time = distance/speed
⇒

t = 700 ÷ 35/3

⇒

t=700×3/35=60

seconds

Go to Question:

Prev Question

Next Question