SSC CHSL 7 Mar 2018 Shift 2 Paper

Section: English Language

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Question : 25 of 100

Marks: +1, -0

ΔDEF is right angled at E. If cotD = 5/12, then what is the value of sinF ?

Your Answer:

Solution:

Given :

cot D =5/12

Also,

cot D ={DE}/ {EF }= 5/ 12

Let DE = 5 cm and EF = 12 cm
Thus, in ∆DEF , ⇒

(DF) ^2 = (DE)^ 2 + (EF) ^2

⇒

(DF)^2 = (5)^2 + (12)^2

⇒

(DF)^2 = 25 + 144 = 169

⇒

DF = √169 = 13

cm
To find :

sin F ={DE}/ {DF}

=

5/13

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