SSC CHSL 7 Jan 2017 Shift 3 Paper

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Question : 69 of 100

Marks: +1, -0

A number is greater than five times its reciprocal by 19/2. Find the number.

11
9
10
8

Solution:

Let the number be

x

According to ques,
⇒

x-(5×1/x)=19/2

⇒

{x^2-5}/x=19/2

⇒

2x^2-10=19x

⇒

2x^2-19x-10=0

⇒

2x^2+x-20x-10=0

⇒

x(2x+1)-10(2x+1)=0

⇒

(2x+1)(x-10)=0

⇒

x=-1/2,10

Since can't be negative, ⇒

x=10

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