SSC CHSL 7 Jan 2017 Shift 3 Paper

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Question : 61 of 100

Marks: +1, -0

If 5A = 13B = 7C; find the value of A : B : C.

91:35:65
65:35:91
35:91:65
7:13:5

Solution:

Let

5A =13B=7C=k

⇒

A=k/5,B=k/13,C=k/7

⇒ Ratio of A : B : C =

k/5:k/13:k/7

⇒

1/5:1/13:1/7

L.C.M. of 5,13 and 7 = 455, thus multiplying by 455, we get :
=

455/5:455/13:455/7

= 91 : 35 : 65

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