SSC CHSL 7 Jan 2017 Shift 3 Paper

Arjun is facing east. He walks 10 m in this direction, then turns left and walks towards north for another 10 m,
then he turns right to walk 25 m east and from there he walks another 10 m towards south. Finally, he walks 50 m to his left towards the east direction.
Thus, distance between his original and final position = 10 + 25 + 50 = 85 m