SSC CHSL 7 Jan 2017 Shift 1 Paper

It is given that ΔDEF ∼ ΔGHI
Also, length of DE = 4 cm and length of the corresponding side GH = 9 cm
⇒ Ratio of Area of ΔDEF : Area of ΔGHI = Ratio of square of corresponding sides = ${\left(\mathit{D}\mathit{E}\right)}^2:{\left(\mathit{G}\mathit{H}\right)}^2$
$=\frac{{\left(4\right)}^2}{{\left(9\right)}^2}=\frac{16}{81}$
∴ The required ratio is 16 : 81