SSC CHSL 7 Jan 2017 Shift 1 Paper

Expression 1 : 2x - 1< 5x + 2
⇒ $5\mathit{x}-2\mathit{x}>-1-2\Rightarrow 3\mathit{x}>-3$
⇒ $\mathit{x}>-\frac{3}{3}\Rightarrow \mathit{x}>-1$ -----(i)
Expression 2 : 2x + 5 < 6 - 3x
⇒
⇒ -----(ii)
Combining equations (i) and (ii), we get :
Thus, the only possible value that can take = 0